select ["性别"],AvgOf(["英语成绩"]),CountOf( * ),groupfunc(["英语成绩"]) from EnglishScore group by ["性别"],groupfunc(["英语成绩"]) end;
// r := sselect * from attrs where lName = lowerCase([0]) end;
// R := select [1].*,[2].["英语成绩"] from A join B on [1].["学号"]=[2].["学号"] end;