tree-sitter test
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select ["性别"],AvgOf(["英语成绩"]),CountOf( * ),groupfunc(["英语成绩"]) from EnglishScore group by ["性别"],groupfunc(["英语成绩"]) end;
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// r := sselect * from attrs where lName = lowerCase([0]) end;
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// R := select [1].*,[2].["英语成绩"] from A join B on [1].["学号"]=[2].["学号"] end;
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